Let s be the sum of the scores without Johnny's score and n be the number of kids in the class except Johnny.
s/n = 71 [this is the average score before Johnny takes it]
(s + 96) / (n + 1) = 72 [average after Johnny takes it]
s / n = 71
s = 71n
Substitute s = 71n into second equation:
(71n + 96) / (n + 1) = 72
Multiply both sides by n+1:
71n + 96 = 72(n + 1)
Distribute:
71n + 96 = 72n + 72
Combine like terms:
n = 24
Add Johnny:
n + 1 = 25
2007-08-21 11:43:00
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answer #1
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answered by whitesox09 7
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Let the number of students = n. Let the total score before John took the test = S.
Before John took the test, we have
S/(n-1) = 71,
i.e., S = 71n - 71.
After John took the test, we have
(S+96)/n = 72,
i.e., S + 96 = 72n.
Simultaneous equations! Subtract the first equation from the second to eliminate S:
96 = n + 71,
so n = 96 - 71.
That means that 25 students took the test.
2007-08-21 11:44:58
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answer #2
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answered by Raichu 6
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The average is the total of all the scores, divided by the number of students.
Let's say there are x students besides Johnny, they all had a combined score of y. Then y / x = 71.
Johnny got a 96, which made the average 72, so this means
(96+y) / (x+1) = 72
You've got two equations with two unknowns. Find x+1, which is the number of students including Johnny.
2007-08-21 11:43:54
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answer #3
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answered by Anonymous
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Let n be the # that took the test without Johnny
the total score is 71n
Johnny took the test later and got 96
the new average = (71n + 96)/(n+1) = 72
71n + 96 = 72(n+1) = 72n + 72
n = 96 - 72 = 24
Including Johnny, n+1 = 25 took the test.
2007-08-21 11:44:18
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answer #4
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answered by vlee1225 6
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Let's use "n" as the number of people in the class, INCLUDING Johnny.
So, you are given that 96 + 71*(n-1) = 72*n
(Johnny's 96 + 71 for everybody else gives a class average of 72)
Now you can solve:
96 + 71n -71 = 72n
96-71 = n
n = 25
So there are 25 people in the class including Johnny.
2007-08-21 11:41:02
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answer #5
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answered by sharky.mark 4
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the old class average was the total of their scores divided by the number of them, T/n = 71. including Johnny's score gives us (T+96)/(n+1) = 72. Solve the 1st one for T, T = 71n, and plug it into the 2nd:
(71n + 96)/(n+1) = 72
71n + 96 = 72(n+1)
71n + 96 = 72n + 72
24 = n,
so including Johnny, class size is 25.
2007-08-21 11:45:40
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answer #6
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answered by Philo 7
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let x = total number of student
[ 71 (x-1) + 96 ] / x = 72
71 x - 71 + 96 = 72 x
x = 25
2007-08-21 11:48:16
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answer #7
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answered by CPUcate 6
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96-71 = 25 students
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Ideas of mental math approach: 96-71 = 25 is the points above the average. Distributing 25 points to everyone, including Johnny to raise the average by 1 means there are 25 students.
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The guy above me put the answer later.
2007-08-21 11:41:24
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answer #8
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answered by sahsjing 7
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What grade are you in? Like 6th? That was REAL hard to me in 6th grade. It's still REAL hard to me now, but I'm getting where I know it. But I stink and HATE math!!! LOL.OK. Let's see. 71-72. 96,. I think the answers 25! But you might want to get the answer from someone else, because I SUCK at math!!!! LOL. I hope I helped!!! :)
2007-08-21 11:45:36
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answer #9
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answered by Anonymous
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Oh geez...
Ehh I hate Albegra.
I start Algebra II when I go back to school Thursday.
*Runs in fear.*
Geometry is soooo easy, Algebra I just suck at.
2007-08-21 11:45:13
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answer #10
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answered by pms_for_sure1304 1
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