Title.
2007-08-21 10:11:37 · 6 answers · asked by GoldRenamon 2 in Science & Mathematics ➔ Mathematics
x^2+5x=0
x(x+5) = 0
x= 0 or x+5=0
x=0 or x=-5
2007-08-21 10:21:35 · answer #1 · answered by Kala 1 · 0⤊ 0⤋
x^2=xx So, you have xx+5x. Take an x out of each term. You get x(x+5). Multiply the x back in and you get the original problem.
Set both factors = to 0 and solve. x=0, x+5=0. The two answers are 0 and -5. Both make the equation true.
2007-08-21 17:20:19 · answer #2 · answered by Ed S 4 · 0⤊ 0⤋
You first factor out the x. You are then left with x(x+5)=0. Then set each section equal to zero. This means x = 0 and x+5 = 0. So, x is equal to 0 and -5.
2007-08-21 17:22:19 · answer #3 · answered by Blondie 5 · 0⤊ 0⤋
x^2 + 5x = 0
x ( x + 5) = 0
So, x = 0 and x = -5 are the two possible solutions.
2007-08-21 17:19:12 · answer #4 · answered by Swamy 7 · 0⤊ 0⤋
i think ur suppose to subtract 5 from 0 which give u -5 (x^2=-5) then square root both side and the answer would be x=square root -5, but since a negative can't have a square root on it the answer is no solution. I am not sure if its right thou.
2007-08-21 17:29:04 · answer #5 · answered by Amber S 1 · 0⤊ 0⤋
(x + 5)(x + 0) =0
therefore x= -5 or 0
Not so sure if zero can be a factor.
2007-08-21 17:22:27 · answer #6 · answered by samfol 2 · 0⤊ 0⤋