Convert the following equations into logarithmic form:?

Question

Convert the following equations into logarithmic form:
a. 9 = 4x
b. 3 = 6y
c. 5 = 7y
d. X = 9y

Answer 1

do you mean
a) 9 = 4^x
where x is an exponent?

Then...
log(4) 9 = x
(log - base 4 - of 9 equals x)

b)
3 = 6^y
log(6) 3 = y

c)
5 = 7^y
log(7) 5 = y

d)
x = 9^y
log(9) x = y

Answer 2

Hello

A basic log form is
y = logb (x) ==== b^y = x

An example would be 2^3 = 8. This is 3 = log2 (8).

a. 9 = 4x ----- 3^2=4x ------ 2 = log3 (4x)
b. 3 = 6y ----- 1 = log3 (6y)
c. 5 = 7y------- 1 = log5 (7y)
d. X = 9y ----- 1 = logx (9y)

Hope this helps

Answer 3

log base with 10 a) 9 = 4x log 9 / log 4 = x b) 3 = 6y log 3 / log 6 = y c) 5 = 7y log 5 / log 7 = y d) X = 9y log X / log 9 = y

Answer 4

I'm not sure what you mean exactly.
However, one way is to take the logarithm on both sides (this preserves the equality).
If A = B
then
Log(A) = Log(B)

a.
Log(9) = Log(4x) = Log(4)+Log(x)
Log(9) - Log(4) = Log(x)
Log(9/4) = Log (x)
therefore:
9/4 = x