2007-08-21 08:34:47 · 7 answers · asked by Mia O 1 in Science & Mathematics ➔ Mathematics
change 34 min 17 sec
= 33 min, 60 sec, 17 sec
= 33 min 77 sec
33 min 67 sec
- 6 min 22 sec
---------------------
27 min 45 sec
2007-08-21 08:47:10 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
Really you cannot do this 4th grade arithemetic problem?
Convert 34 min 17 sec into 33 min 77 sec and now subtract 6 min 22 sec and you have the answer
2007-08-21 15:43:07 · answer #2 · answered by GTB 7 · 0⤊ 0⤋
Subtraction:
= (34 min, 17 sec) - (6 min, 22 sec)
= ([34 - 1] min, [17 + 60] sec) - (6 min, 22 sec)
= (33 min, 77 sec) - (6min, 22 sec)
= 27 min, 55 sec
Answer: 27 min, 55 sec
2007-08-25 07:37:55 · answer #3 · answered by Jun Agruda 7 · 3⤊ 0⤋
27 minutes and 55 seconds
To subtract a larger seconds value from a smaller one, you have to borrow one (1) minute from the total minutes. This adds 60 seconds to the smaller seconds value, and you can do the subtraction.
34:17 - 6:22 = 33:77 - 6:22 = 27:55
2007-08-21 15:42:33 · answer #4 · answered by Dave 6 · 0⤊ 0⤋
27 min. 55 sec.
2007-08-21 15:43:30 · answer #5 · answered by itsjustme 2 · 0⤊ 0⤋
27 min. 55 sec.
2007-08-21 15:43:23 · answer #6 · answered by Anonymous · 0⤊ 0⤋
It is like normal subtration, but you need to borrow 60sec from the 34 min.
so it would be 33min, 77sec - 6min 22sec=
27min 55 sec.
2007-08-21 15:44:28 · answer #7 · answered by Tom . 2 · 0⤊ 0⤋