The speed of light is about 3.0 108 m/s. Express the speed of light in terms of astronomical units per minute?
2007-08-21 07:35:53 · 7 answers · asked by Wonder 2 in Science & Mathematics ➔ Physics
(3.0 x 10^8 m/s)(1km/1000m)(1AU/1.5 x 10^8km)(60s/min)
= 0.12 AU/min
2007-08-21 07:51:19 · answer #1 · answered by Anonymous · 0⤊ 1⤋
An Astronomical Unit Au Is
2016-11-11 05:10:17 · answer #2 · answered by ? 4 · 0⤊ 0⤋
This is really a math problem, not a physics problem. You are just converting between one set of units and another.
One easy way to do that, is to write down the initual value that you know, and then multiply it by fractions which are equal to 1, and which have different units in the numerator and denominator. An example of such a fraction is:
(60 sec)/(1 minute)
The reason this is equal to "1" is that the numerator is equal to the denominator (i.e., 60 sec is equal to 1 minute). You could just as easily call it (1 minute)/(60 sec).
By choosing those fractions carefully, you can get some of the units to "cancel out," and so you'll be left with only the units you want to end up with. A unit will "cancel out" if appears in the numerator of one fraction and in the denominator of another fraction.
In your case, start with:
(3.0x10^8 m/sec)
Then multiply by these fractions, each of which equals 1:
(60 sec/ 1 min)
(1 km / 1000 m)
(1 AU / 1.50x10^8 km)
When you do this, the "sec", "m", and "km" all cancel out, and the final units will be "AU / min" (AU per minute).
2007-08-21 07:57:01 · answer #3 · answered by RickB 7 · 1⤊ 0⤋
Do you mean 1.50 x 10^8 km?
One AU is actually slightly *less* than the average distance between the Earth and the Sun. 1 AU = 149,597,870,691 meters.
The length of the meter is defined so that the speed of light is exactly c = 299,792,458 m/s.
And of course, 1 minute = 60 seconds
Divide AU by c, = 499.005 seconds
Divide by 60 = 8.31675 minutes.
Using your values, it would be 1.50 / 3.0 = 500 seconds = 8.33333 minutes.
2007-08-21 07:50:54 · answer #4 · answered by morningfoxnorth 6 · 0⤊ 0⤋
Kepler's third regulation breaks right down to: Semi significant axis (in AUs) ^ 3 = era (in years) ^2 Plug interior the numbers and notice if the facets are equivalent. in the event that they are, then sure the asteroid obeys K3L. i'm no longer doing it for you.
2016-12-12 08:44:33 · answer #5 · answered by bartelt 4 · 0⤊ 0⤋
I think that 1 AU would be equivalent to about 7.833 minutes.
2007-08-21 07:52:43 · answer #6 · answered by musiclover 3 · 0⤊ 0⤋
1AU/8min
2007-08-21 07:49:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋