My inground swimming pool is 32 X 18 and 10 feet deep in the deep end and 3 feet deep in the shallow end?

Question

so how many gallons thousand gallons is it? I need to know so I'll know how much alkalinity up to put in it. Thanks

there is a big drop off going to the deep end, it's very steep

Answer 1

Assuming that the slope from deep end to shallow end is perfectly linear (though not probable) you could estimate the pool to be 32 x 18 x 6 1/2. (6 1/2 would be the average depth given the previous assumption.)

32 x 18 x 6.5 = 3744 cubic feet.
using www.onlineconversion.com
>>3 744 cubic foot = 28,007.064935065 gallon [US, liquid]

28,007 gallons approximately.

Answer 2

I have the same dimensions

1 assume its a square pool and the slope to the deep end starts 10' from the shallow. we'll also assume that the slope ends 10' from the end of the deep end.

V = volume of the pool 3' deep + the volume of the slope section + volume of the deep end

V = 32*18*3 + 1/2*12*7*18 + 10*18*7
V = 3744 ft^3
V = 23300 gallons.

I would use for 20,000 gallons

Answer 3

The volume in ft^3 is:
32 * 18 * (10 + 3) / 2
= 3744 ft^3
= 23321 UK gal
or 28007 US liquid gal.

Late extra:
A non-uniform slope, as suggested by your additional comment, unfortunately invalidates our answers. We now need to know how near the deep end the 'drop off' starts, and the depth just before it starts. Then we can be a bit more accurate.

Answer 4

The volume of the pool is (the rectangular volume plus the wedge shaped volume):

32*18*3 + (1/2)32*18*7
1728 + 2016 = 3744 cubic feet

1 cubic foot = 7.48 gallons

3744*7.48 = 28005.12 gallons of water are in your pool

Answer 5

assuming that the pool depth changes linearly from 10 feet at one end to 3 feet at the other, so no flat bits at either end then the pool requires 28,000 gallons