Calculate the area of the triangle with the following vertices:
(-5, -7), (-1, -7), (-3, -4)
A 10 sq units
B 14 sq units
C 4 sq units
D 6 sq units
E 9 sq units
F 17 sq units
2007-08-21 05:50:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Two of the points you list are on a horizontal line. They are the best pair to use as your base.
How far is the third point from that line? That's the height.
A=bh/2.
2007-08-21 05:57:03 · answer #1 · answered by Doc B 6 · 0⤊ 0⤋
A = 1/2*6*3 = 9
Ans: E
2007-08-21 12:55:58 · answer #2 · answered by gebobs 6 · 0⤊ 0⤋
If you plot these points, you'll see a triangle with a base of 4 and a height of 3.
A = 1/2b * h.
The answer is D
2007-08-21 13:01:48 · answer #3 · answered by Jonathan B 3 · 0⤊ 0⤋
Area of triangle with coordinates (x1, y1), (x2, y2), (x3, y3) =
(1/2)[x1(y2 - y3) + x2 (y3 - y1) + x3(y1 - y2)]
substituting the values
A = (1/2)[-5(-7 - (-4)) + (-1) (-4 - (-7)) + (-3)(-7 - (-7))]
= (1/2)[-5(-3) + (-1)(3) + (-3)(0)]
= (1/2)[15 - 3 - 0]
= (1/2)(12) = 12/2 = 6
So area of triangle = 6 square units -- (D)
2007-08-21 13:21:57 · answer #4 · answered by mohanrao d 7 · 0⤊ 0⤋
c....not absolute though
2007-08-21 12:57:22 · answer #5 · answered by Anonymous · 0⤊ 0⤋