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2 answers

I assume we're not observing from the sun but comparing apparent heights or sizes to each other and to that of the sun. If the two objects are equal in elevation, their height to distance ratios are equal to each other. If you're talking about objects also being the same apparent size as the sun, the situation is similar, only now the similarity extends to the ratio of the sun's size (~800,000 mi) to its distance (~93,000,000 mi).
1st answerer: Nothing says that two unequal-sized objects will look equal if you get far enough away. If you can see them at all, their size-to-distance ratios will determine their apparent angular size ratios.

2007-08-24 06:47:39 · answer #1 · answered by kirchwey 7 · 0 0

angular elevation of 2 objects (say 2 objects on earth) wrt sun is equal because the dimensions of the two objects are very less in comparison to the distance between sun and the objects. for example consider mt everest(i guess its 7000m) and a guy who is 2 metres tall. angular elevation is the angle subtended by the object in the eye of an observer. since the observer is on sun, which is at a huge distance in comparison to the dimensional difference of man and mountain, both these bodies will subtend equal angles and hence will have equal angular elevation. but one must keep in mind that if you are observing considerably huge bodies, then they will have different angualr elevations. angular elevations being equal do not have anything to do with observation from sun. it is just an interplay of "distance between the observer and the observed" and "dimensions of the observed".

2007-08-21 14:52:19 · answer #2 · answered by NAVANEETH K P 2 · 0 0

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