2007-08-21 04:38:13 · 17 answers · asked by Anthony W 1 in Science & Mathematics ➔ Mathematics
x + (x + 2) + (x + 4) = 81
3x + 6 = 81
3x = 75
x = 25
25 + 27 + 29 = 81.
2007-08-21 04:41:40 · answer #1 · answered by Edgar Greenberg 5 · 4⤊ 0⤋
If n is an integer, then an odd number is
2n+1, the next 2n+3, and the last consecutive 2n+5
Add them to make 81
2n+1 + 2n+3 + 2n+5 = 81
6n = 81 -1-3-5 = 81 -9 = 72
n = 72/6 = 12
The numbers are
2n+1 = 24+1 = 25
2n+3 = 27
2n+5 = 29
2007-08-21 04:45:04 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋
let the 3 consecutive odd numbers be x , x+2 and x+4
=> x+(x+2)+(x+4)=81
=>3x+6=81
=>3x=81-6
=>3x=75
=>x=75/3
=>x=25
first odd number=x=25
second odd number=x+2=25+2=27
third odd number=x+4=25+4=29
and since 25+27+29=81
therefore the answer is correct
:)
2007-08-21 04:45:38 · answer #3 · answered by ? 2 · 0⤊ 0⤋
let x be the odd no.
therefore
=> x +x+2+x+4 = 81
=> 3x+6 = 81
=> 3x+6 = 81
=>x =25
the 3 nos are 25, 27,29
chk 25+27+29 = 81
2007-08-21 04:43:28 · answer #4 · answered by herbman76 2 · 0⤊ 2⤋
25 27 29
2007-08-21 04:41:26 · answer #5 · answered by Jessie H 6 · 0⤊ 2⤋
25+27+29
2007-08-21 04:41:35 · answer #6 · answered by Anonymous · 0⤊ 2⤋
If I understand you question right, I think that the answer is 25, 27, 29. They add up to 81.
2007-08-21 04:42:19 · answer #7 · answered by jaymikem08 1 · 0⤊ 1⤋
you obviously know what the answer is, but i'll offer a different solution to whats been posted:
Let x be any integer.
Consecutive integers:
1. 2n-1
2. 2n+1
3. 2n+3
(2n-1)+(2n+1)+(2n+3) = 81
6n+3=81
6n = 68
n = 13
Plug in n:
1. 2(13)-1 = 25
2. 2(13)+1=27
3. 2(13)+3=29
ANS: 25, 27, 29
2007-08-21 04:47:10 · answer #8 · answered by miggitymaggz 5 · 0⤊ 0⤋
What's 81 divided by 3? Take that number then subtract 2 to get the second number. Take the product and add 2 to get the third number.
2007-08-21 04:42:45 · answer #9 · answered by Justin H 7 · 0⤊ 2⤋
25, 27, 29
2007-08-21 04:42:20 · answer #10 · answered by Anonymous · 0⤊ 1⤋