Mark McGuire hit a baseball with an initial speed of 180 feet per second at an angle of 40 degrees to the horizontal. The ball was hit at a height of 3 feet of the ground.
(a) When is the ball at its maximum height? Determine height of the ball.
(b) Determine the distance that the ball travels.
2007-08-21 01:02:52 · 2 answers · asked by journey 1 in Science & Mathematics ➔ Mathematics
h= -16t^2 +180*sin 40º t+3
h´= -32t+115.7 = 0 so t = 3.62 s for max height
hmax=212.66 feet
time to reach height of three feet again
t= 115.7/16=7.23 s
distance = 180 *cos40º *7.23 =997 feet
2007-08-21 02:51:56 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
a) you didn't tell us the date and time the ball was hit, so how can we answer this question? Not enough data!
b) it depends on the height of the ground where it hits. Again there's not enough data. If the ground is higher it will land sooner than if the ground is lower. Hey it might even fall into a lake and sink slowly.
2007-08-21 08:11:51 · answer #2 · answered by dweebken 5 · 0⤊ 1⤋