anyone can solve this equation?

Question

solve 2x+2x-3z=5
4y+3x+5y=4
and
3y+4x+5z=3

pls solve this by gauss jordan and determinant!
pls show ur solutions! tnx in advance!

Answer 1

I cannot believe that there are two x terms in the first equation and two y terms in the second.

I think the G-J method consists of using row transformations to put the augmented matrix into an upper triangular matrix, and then solving from the bottom up.

For example, if the given problem were
2x + 2y + 3z = 5
3x + 4y + 5z = 4
4x + 3y + 5z = 3, your work would look like the following.

2 2 3 5
3 4 5 4
4 3 5 3 .

2 2 3 5
0 1 1/2 -7/2
0 -1 -1 -7

2 2 3 5
0 1 1/2 -7/2
0 0 -1/2 -21/2 .

The third row represents the equation (-1/2)*z = -21/2, so
z = 21. Using this in the equation from the second row, we have y + (1/2)*z = y + 21/2 = -7/2, so y = -14. Finally, using the known values for y and z in the first equation, we have
2x + 2*(-14) + 3*21 = 5, so x = -15.

You should be able to mimic this technique for your problem.