Word problem neew some help?

Question

To determine the number of deer in a game preserve, a conservationist catches 803 deer, tags them and lets them go. later 400 deer are caught, 200 of them are tagged, how many deer are in the preserve?

Answer 1

since 803 deer were caught initially that means there are a minimum of 803 deer in the preserve.
after the 803 were released and 400 were recaught. out of these 200 were the tagged deer, means these 200 were caught earlier too and they were amongst the 803 deer that were initially caught.
so the number of new deer caught=total caught deer- the tagged deer = 400 - 200 = 200
so the total number of deer in the preserve are atleast 803+200 = 1003

Answer 2

Assuming the tagged ratio in the second catching reflects the ratio of all the deer in the preserve:
200/400=50% tagged
If 50% of the deer in the preserve are tagged, then "x" times 0.50=803.

"x"=1606

Word problems leave so much to be desired. Hey teachers, we need all the variables covered before we can give an accurate answer. Were all the deer in the preserve caught one of those two times? Were half of the second series of deer tagged in the first catching or were these all new deer?

Answer 3

I will assume that none of the deer have met with foul play and that each of the selected samples are completely random. I would guess that there are around 1606 deer since originally I tagged 803 deer and my later sample had 50 percent tagged deer (or one tagged deer for every two deer caught).

Answer 4

The way to answer this is to use proportion.
We represent the total number of deer using x.
803:x=200:400
Multiply the means and the extremes and you get
200x=321200
200x/200=321200/200
x=1606
So there are 1606 deer in the preserve.

Answer 5

803+400-200=n
803+200=n
n=1,003 deer