The speed of a train A is 10 mph slower than the speed of train B Train A travels 200 miles in the same time it takes train B to travel 250 miles. Find the speed of each train
2007-08-20 19:27:25 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
I got Train A=40mph, Train B=50mph
Hint: Time=Distance/Velocity.
2007-08-20 19:38:41 · answer #1 · answered by BioSci 1 · 0⤊ 0⤋
let x = speed of train B
x-10 = speed of train A
now...
speed = distance / time
or
time = distance / speed
thus, since
time of travel of train A for 200 miles = time of travel of train B for 250 miles... then
200 / (x-10) = 250 / x
or 200x = 250x - 2500
50x = 2500
x = 50 mph (speed of train B)
thus
x-10 = 50 - 10 = 40 mph (speed of train A)
2007-08-20 19:45:01 · answer #2 · answered by quigonjan 3 · 0⤊ 0⤋
A = B - 10
250 = Bt and t = 250/B
200 = At = (B - 10)t
200 = (B - 10)(250/B)
200 B = 250B - 2500
50B = 2500
B = 50
Train B travels at 50 mph and A at 40 mph
2007-08-20 19:44:13 · answer #3 · answered by Captain Mephisto 7 · 0⤊ 0⤋
Train A is moving at 40 mph for five hours.
Train B is moving at 50 mph for five hours.
hope that helped you :)
P.S. this was a simple math question, I am not sure why you ask it in physics.
2007-08-20 22:55:03 · answer #4 · answered by Thoughtfull 4 · 0⤊ 0⤋
Train A 24mph & train B 25mph, i think !, no i think am way outa ma depth there, ask me one on ?
2007-08-20 19:38:48 · answer #5 · answered by Anonymous · 0⤊ 0⤋