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first measurement is 1.28, second measurement is 1.63...what percentage did the measurement increase by?

2007-08-20 18:47:05 · 5 answers · asked by mhovanes21 2 in Science & Mathematics Mathematics

Thanks for the answers...sometimes when you dont use this stuff in awhile you get brain block...if you knew how old I was and what degree I have you would get a good laugh.

Thanks again.

2007-08-20 19:00:32 · update #1

5 answers

To find percentage increase we need to create a percentage:

Second/First >>> 1.63/1.28

This equates to 1.2734375

Now we subtract 1 (that's excess stuff) and multiply by 100, to get our percentage:

1.2734375 - 1 = 0.2734375
0.2734375 * 100 = 27.34375%

2007-08-20 18:53:30 · answer #1 · answered by Anonymous · 2 0

To work out the percentage change divide the second number by the first number:

1.63 / 1.28 = 1.27 (1)

Then subtract 1:

1.27 - 1 = 0.27 (2)

And multiply by 100:

0.27 * 100 = 27 (3)

So the measurement has increased by 27%.

If the number at step 2 is negative it represents a decrease.

2007-08-20 18:54:14 · answer #2 · answered by juniper 2 · 0 1

To work out percentage increase you must firstly find the difference between the two wages: £7.20 - £6.50 = £0.70 Now to work this out as a percentage you use this format: (Difference divided by Original value) x 100% So... (£0.70 / £6.50) x 100% = 10.769...% To an appropriate degree of accuracy would probably be around 10.77% (as there are 2 decimal places in the question) Hope that helps!

2016-05-18 21:20:32 · answer #3 · answered by ? 3 · 0 0

Increase = 0.35
% increase
= (0.35 / 1.28) x 100%
= 35 / 1.28 %
= 27.3 % (to 1 decimal place)

2007-08-20 19:37:49 · answer #4 · answered by Como 7 · 2 0

27.3%

1st= 1.28
2nd = 1.63

diff = 1.63 -1.28 =0.35
% = diff /1st * 100
= 0.35/1.28 *100
=27.3

2007-08-20 18:53:38 · answer #5 · answered by sv1973 2 · 0 0

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