ab=52 and a+b=17?

2 ⤊

2007-08-20 18:14:47 · 4 answers · asked by xxbabycheekzix 1 in Science & Mathematics ➔ Mathematics

4 answers

a = 17 - b
(17 - b) (b) = 52
17b - b² = 52
b² - 17b + 52 = 0
(b - 4) (b - 13) = 0
b = 4 , b = 13
a = 13 , a = 4

2007-08-20 19:48:38 · answer #1 · answered by Como 7 · 2⤊ 0⤋

a.b=52=>a=52/b . So a+b=17=>52/b+b=17=>
52+b^2=17b=>b^-17b+52=0 =>
b=(17+sqrt(17^2-4*52))/2=13 and a=4
or
b=(17-sqrt(17^2-4*52))/2=4 and b=13

2007-08-21 01:24:37 · answer #2 · answered by BFG9000 2 · 0⤊ 0⤋

a=13 b=4 or vice versa

2007-08-21 01:21:20 · answer #3 · answered by DanYell 3 · 0⤊ 1⤋

I hope you don't just expect an answer.

First, solve for one variable in terms of the other.

Substitute that into the other equation and solve for the other variable.

2007-08-21 01:23:06 · answer #4 · answered by Brainiac 2 · 0⤊ 0⤋