algebra questions?

Question

(3a^3b^5)(50a^2b^3)

(14z^3-28)/7z

please explain both thanks

Answer 1

1. (3a^3 b^5)(50a^2 b^3) >>Using FOIL method.
= 3(50) a^3+2 b^5+3 >>Adding indices of numbers with the same base if multiplication.
= 150 a^5 b^8

2. (14z^3 - 28) / 7z >>You cannot divide an algebraic expression by a term, you must separately divide every term of the expression by a term.
= 14z^3 / 7z - 28 / 7z >>Divide every term by 7z
= 2z^2 - 4 / z >>Factorize
= 2(z^2 - 2 / z)

REMEMBER :
>a^m x a^n = a^m + n
>a^m / a^n = a^m - n

Answer 2

It's actually like this:
Remember: when multiplying you just multiply the numbers then add the exponents:

so:
(3a^3b^5)(50a^2b^3)

will become:
150a^5b^8


next:

14z^3 - 28
---------------
7z

will be:
2z^2 - 4/z

simplified:

2(z^2 - 2/z)

Answer 3

You are multiplying two monomials. So you multiply constants times constant and each variable times the same variable. If variables have exponents, the exponents are ADDED.

You are dividing a binomial term by 7z. You can factor out constants with constants, and terms in the variable z with z. If variables have exponents, the the exponent of the denominator variable is SUBTRACTED from that of the numerator variable.

Answer 4

combine like terms and work from there. if you don't understand it ask your teacher (if you are in school) .........on the first one....have you ever heard of the tick-tack-toe method or the F-O-I-L method? it's simple just tick-tack-toe it.........put your first portion of your problem on top and the second half on the side like a tick-tack-toe board and multiply that way....in your second problem just find your highest power of "z" and subtract your lowest one from it. and work the rest of the problem out from there.

Hope that I helped you out just a little...I know how confusing math can be..I'm starting pre-calculas in a couple of days.