math homework?

Question

hello,can u help me w/my math homework?i have to simplifly the expression (i did some of them,but i need u to check them n see if its correct....im new to this.but i didnt do the first one.if i get it wrong,can u tell me in the most easiest way how did u get your answer..?thnks!)

1. 3x+x
2. 4y+5y=9y
3. 2z+6z+10=8z+10
4. 3a+2t+8s+4=9a+5b
5. 3z+7+6z+2=9z+7+2
6. 15z+5+6z=21z+5
7. 3s+2t+8s+4=11s+2t+4
8. 12x+3y+4+6y=12x+9y+4
9. 6x+2+4x+9=10x+2+9

the rest is the same,simplify the expression:
10. 4a+6a+2a (to the 2nd power)
11. 5z+2z+6z (to the 2nd power)
12. x(to the 3rd power)+2x(to the 2nd power)+x(to the third power)
13. 3(y+2)+6y
14. 8(z+1)+2(z+4)
15. a(b+2)+3ab+4

*thnks!

Answer 1

You can combine like terms. That means that 3y plus 2y equals 5y. Because whatever y is, it is the same thing no matter what you do to it.

So if y equals 2, then 3x2=6, and 2x2=4 and 6+4=10.

Your homework, what I scanned of it is correct.

Math is a beautiful subject because if you know your basic operations, you can always check your work by plugging in a number for each variable and see if it works out right.

Answer 2

This is too many problems in one question. I Can try to help you though. What you need to do is add the coefficients(numbers) of the matching variables(letters). For example, the answer for 1 is 4x. If there is no coefficient next to the variable, then it's actually 1. The one is implied.
2 and 3 are correct, but 4 is wrong. For number 5 and 9, you can add the numbers without variable to further simplify, for example, in number 5, you can add the 7 and 2 and you get 9z+9. 6, 7, and 8 are correct.

For the second set (10-15) try to do the same, but treat a variable to a power as a different variable. so #10 would just be 10a+2a(to the second power) and #12 is 3x(to the third power)+2x (to the second power)

For 13-15, you need to mulitply it all out beofre adding the like terms. #13 is 3y+6+6y, then add the like terms to get 9y+6

If you get confused, just thinkit through and take it one step at a time.

GL!

Answer 3

1. *hint* If you see an "x" by itself... it's the same as saying "1x".... so knowing that, since I see that you know how to add "like" terms as you did in Problem 2. .... now you just do the same for Problem 1... just with "x" terms. Anytime you see a letter variable by itself... it's the same as having an imaginary "1" in front of it. 1y = y ..... 1x = x..... 1w = w.... see?
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4. You have to double check your work... it doesn't make sense the way you typed it...
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5. You can "combine" (add) the 2 and 7.... 2+7 = ?
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9. Again... just as in Problem 5., here you can "combine" the numbers... so what is 2+9? 2+9 = ?
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10. 4a+6a+2a (to the 2nd power) = ... you can combine the 4a and the 6a.... but the 2a^2 stays the same.... so you have ___a + 2a^2.... you just have to fill in the blank...
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11. 5z+2z+6z (to the 2nd power)

Same as in 10. You can combine the 5z and the 2z... but the 6z^2 stays the same... so you have ___z + 6z^2.... you just have to fill in the blank...
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These, you first have to take care of the ()'s.... for example... in 13. you have to multiply each of the terms in the parentheses (the "y" and the +2) each by the 3 in front... so 3(y+2) = (3)(y) + (3)(+2) = 3y + 6... but don't forget to add the 6y.... because your given problem is 3(y+2) + 6y...

This is how your work should look for Problem 13. Watch closely...

13. 3(y+2)+6y = (3)(y) + (3)(2) + 6y = 3y + 6 + 6y...

But you aren't done yet... because you can combine "like" terms.... The "+6" stays by itself... but you can combine 3y and 6y.... so your final answer should be "9y + 6"

Okay... so I'm leaving 14. and 15. for you to do...

first expand the #(_ + _) .... by multiplying each term inside the ()'s by the # in front... In problem 14. you first expand 8(z+1) by multiplying "z" and "+1" each by 8.... you do the same with 2(z+4).... after you have done that.... add all the "like" terms together... so add the 8z and the 2z..... and combine the numbers together also.... you should be adding an 8 and another 8.... then you will have your final answer...

14. 8(z+1)+2(z+4)

Same thing ... expand #(_ + _ ) first..... then combine "like" terms... you know you are doing the math correctly if when you are combining your terms, you are adding an "ab" term and a "3ab" term and if you also have a "2a" term and a "+4" in your answer...

15. a(b+2)+3ab+4

Answer 4

For #1, think 3x+1x
#2, #3 are right, don't know what you are doing with #4, maybe a typo?
#5 not finished because you still have 7+2

#10, #11 is the whole thing to the second power?
#13, #14, #15 take care of the () first
example #13 3(y+2)+6y =3y+6+6y=9y+6

Hope this helps

Answer 5

3) 2z+6z+10=8z+10=tthe exercise
8z+10=8z+10
8z-8z=10-10
0=0
now do the samething for the other one

10) (4a+6a+2a) second power
12(a)second power

13) 3(y+2)+6y
3y+6+6y
9y+6



now do the others.

Answer 6

Well if you really need some help on your math than you should be staying here asking question you can join the online courses for free to help and enhance you knowledge that will be really helpful.