Finding the x-intercept of a Parabola?

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Finding the x-intercept of a Parabola?

I need to know how to find the x-intercept for the parabola y=x^2-5x+3.

2007-08-20 14:57:25 · 2 answers · asked by Connie 2 in Science & Mathematics ➔ Mathematics

2 answers

Set the equation equal to zero and solve for x.

y = x² - 5x + 3

x² - 5x + 3 = 0
x = [5 ± √(5² - 4*1*3)] / (2*1)
x = [5 ± √(25 - 12)] / 2
x = [5 ± √13] / 2

2007-08-20 15:07:14 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋

Put 0 in for y and solve (use quadratic formula). Note: there will be two x-intercepts.

2007-08-20 22:01:11 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋