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Perform the indicated operations: 2√[48] + 7√[12] –√[27]

2007-08-20 13:18:27 · 3 answers · asked by wendiemail 1 in Science & Mathematics Mathematics

3 answers

I'm going to use r for the square root symbol, since this (not my own) keyboard doesn't have the numeric keypad.

2r48 + 7r12 - r27 =
2r(16*3) + 7r(4*3) - r(9*3) =
2*4r3 + 7*2r3 - 3r3 =
8r3 + 14r3 - 3r3 =
19r3

2007-08-20 13:27:05 · answer #1 · answered by Philo 7 · 0 0

2*4*sqrt(3) + 14*sqrt(2) - 3*sqrt(3) = 5sqrt(3) + 14sqrt(2):

sqrt(48) = sqrt(16*3) = 4 sqrt(3)
sqrt(12) = sqrt(4*3) = 2 sqrt(3)
sqrt(27) = sqrt(9*3) = 3 sqrt(3)

2007-08-20 13:24:45 · answer #2 · answered by John V 6 · 0 0

sqrt48=4sqrt3, because 2*2*2*2*3 = 48

sqrt12=2sqrt3, because 2*2*3=12

sqrt27=3sqrt3, because 3*3*3=27

So...
2*4*sqrt3+7*2*sqrt3-3*sqrt3
=8sqrt3+14sqrt3-3sqrt3
=19sqrt3

2007-08-20 14:08:22 · answer #3 · answered by Anonymous · 0 0

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