In wandering, a gizzly bear makes a displacement of 1563m due west, followed by a displacement of 3348 m in a direction of 32 degrees north of west. What are the magnitude and the direstion of the displament needed for the bear to return to its starting point? specify the direction relative to due east.
2007-08-20 11:20:10 · 2 answers · asked by Joann 2 in Science & Mathematics ➔ Physics
The last leg has resolved vectors:
N: 3348 sin32 = 1774
W: 3348 cos32 = 2839
The entire trip has resolved vectors:
N: 1774
W: 2839 + 1563= 4402
The magnitude of the return:
(1774^2 + 4402^2)^0.5 = 4746
The angle is invsin(1774/4746) = 21.9 deg S of E
2007-08-20 11:36:19 · answer #1 · answered by gebobs 6 · 1⤊ 0⤋
as above (gebobs answer), but for one thing his final answer for angle - or direction is wrong
question asks for angle relative to due East!
so his calculated angle of 21.9 is between due west and the final displacement vector. to find the diff between E and this vector add 180 degrees to get.
201.9 South of East
as in all the way round from E and then up further 21.9
2007-08-23 14:59:47 · answer #2 · answered by pat_arab 3 · 0⤊ 0⤋