how would i graph this?

Question

3x^2-18x+25 ?

please help me! i would really appreciate it!

Answer 1

Make a chart one side x values which are -3,-2,-1,0,1,2,3,4,etc.
On the other side of this chart you will have the vales that you get when you solve equation using these x values. For exampleLet x=o
3(o)^2 - 18(O) +25 = 25
X is 0 and Yis 25 now put it in the graph Easy. Hopefully it will help you.

Answer 2

Since 3x^2 is positive, the parabolais concave up like a U.
The axis of symmetry is x = -b/2a = 18/6 = 3So everything to the left of the line x = 3 is the reflection of everything to the right of the line x = 3.

The vertex lies on the axis of symmetry and is (3, -2).
You get the -2 by evaluating f(3).

Using the quadratic equation, 3x^2-18x+25 has roots at
x = 3 +/- (1/3)sqrt(6). Now just pick a few more points such as (1, 10) (0,25) and you should be able to plot the curve.

Answer 3

Graphing calculator!!!=)

It's a parabola with y-intercept at 25, and x intercepts between 2&3 and 3&4.

Find x & y intercepts by substituting 0s.

x-int:
y=3(0)^2-18(0)+25

y-int:
0=3x^2-18x+25

good luck, hope I helped!

Answer 4

without using a table you could

1st solve
3x^2-18x+25 = 0
=> (3x - 5)( x - 5 ) = 0
=> x = 5/3 OR x = 5
crosses X axis at these pts (5/3 ,0) & ( 5 , 0)

cuts Y axis i. e. let x= 0
y = 3(0)^2-18(0)+25 = 25
crosses Y axis at ( 0 , 25 )


+ x^2 graph => u shaped