Hard Advanced Algebra Problem????

Question

Use the tagging and recapturing technique to estimate the number of fish in a pond. Suppose 140 fish were captured, tagged, and released. Then 50 fish were recaptured and among them 20 were found to be tagged. Estimate the number of fish in the lake.

Answer 1

20/50 = 140/x

50*140 = 20*x

x = 350

Answer 2

Hard? Advanced Algebra? Give me a break.
If 20 of 50 fish are tagged, that means that the initial 140 represented 40 percent of the fish in the pond. So 140/0.4 = 350 fish.

Answer 3

Since 20 of the 140 tagged fish (1/7) were caught, that means 50 should be 1/7 of the total fish. So multiply 50 by 7.

Answer 4

its not that advanced or hard... I learned this in 6th grade.
the answer is: 350 fish.
heres how you get it: 20 of the tagged fish represents the 140 fish. so all you have to do is divide 20/50 (2/5) to 140. since you have to make 140 reciprocal, 140 becomes 1/140. so 2/5 times 1/140 equals 2/700. 2/700-1/350.
so 350 fish is your answer.

Answer 5

because a hundred and fifty = a million * 2 * 3 * 5 * 5 Your options are a million m by skill of a hundred and fifty m; fence length = 2 (a million + a hundred and fifty) = 302 m 2 m by skill of seventy 5 m; length = 2 (2 + seventy 5) = 154 m 3 m by skill of 50 m; length = 2 (3 + 50) = 106 m 5 m by skill of 30 m; length = 2 (5 + 30) = 70 m 6 m by skill of 25 m; length = 2 (6 + 25) = sixty two m 10 m by skill of 15 m; length = 2 (10 + 15) = 50 m a 10 m by skill of 15 m fence will require the smallest volume of fencing. A sq. fence, ? a hundred and fifty = 12.25 m on a element, could be in basic terms 40 8.ninety 9 m in length, and a around one, circumference = 40 3.4 m, could be even smaller, however the concern fact did not enable those.

Answer 6

350