thanksmucho
2007-08-20 06:54:45 · 6 answers · asked by lasfklaf; 1 in Science & Mathematics ➔ Mathematics
First, subtract 2x from both sides of the equation:
-3y = -2x - 8
Now, divide both sides by -3 to get:
y = (-2x - 8) / -3 <==== FINAL ANSWER
I hope that helps you out! Please let me know if you have any other questions!
Sincerely,
Andrew
2007-08-20 07:17:01 · answer #1 · answered by The VC 06 7 · 0⤊ 1⤋
2x-3y=-8
add 3y to both sides to get rid of the -3y on the left
2x=3y-8
add 8 to both sides to get rid of the -8 on the right
2x+8=3y
divide both sides by 3 to get y by itself
y=(2/3)x+(8/3)
hope this helps
2007-08-20 14:04:32 · answer #2 · answered by krazyraider0516 2 · 1⤊ 2⤋
3y = 2x + 8
y = (2/3) x + 8/3
2007-08-20 14:01:23 · answer #3 · answered by Como 7 · 1⤊ 1⤋
y=(2 x+8)/3
2007-08-20 14:05:01 · answer #4 · answered by Dhip 2 · 0⤊ 2⤋
2x-3y=-8
-3y = -8 -2x
3y = 8 + 2x
y = (8+2x)/3
Greetings
2007-08-20 14:05:27 · answer #5 · answered by Gilarh 3 · 0⤊ 2⤋
2x-3y=-8
-3y=-2x-8
3y=2x+8
y=2/3x+8/3
2007-08-20 14:14:24 · answer #6 · answered by Sarbinargh 4 · 0⤊ 2⤋