what is the probability of getting a 2 on two dice?

Answer 1

There are clearly several different possibilities for what you are asking. Some answerers are addressing one, some another, and none very thoroughly.

All of these cases involve the basic formula:

p = (# desired outcomes) / (# total outcomes).

Here, there are 6×6 = 36 total possible outcomes.

Case 1: The probability of two dice SUMMING to 2
Case 2: The probability that one (or both) of them is 2.
Case 3: The probability that both will be a 2.

Case 1:

There is only one outcome that sums to 2: 1+1=2. Thus the answer here is 1/36.

Case 2:

Here it's a bit trickier. There are 6 outcomes when the first dice is a 2, and 6 when the second is a 2, but those two sets of 6 share (2,2) in common. So there are really only 11 outcomes with one or more 2s showing. So here it is 11/36.

Case 3:

There is obviously only one outcome that gives this result. So you have a probability 1/36.

Answer 2

since there are 36 possible outcomes, the probability that both dice will get 2 is 1/36 or 0.028

or can also be computed as probability of event A and event B occuring simultaneously. denoted as P(A intersection B). intersection is represented by an inverted letter U... not available in my keyboard
event A= getting 2 on the first dice
event B = getting 2 on the second dice

since on dice#1 there are 6 possible outcomes(1,2,3,4,5,6)
the probability of getting "2" is 1/6... the same is the case for for dice#2
since P(A intersection B) = P(B) * P(A)
= 1/6 * 1/6
= 1/36
= 0.028
i hope this helps...
*by the way... P(A intersection B) = P(B) * P(A) can only be used for independent events... that is if the events does not affect the occurence of the other.

Answer 3

If what u are referring to is getting 2 on each of the 2 dices thrown at once, then the answer is (1/6 * 1/6 = 1/36)

Answer 4

The probability of getting a 2 would be the probability of getting a 1 on one die times the probability of getting a 1 on one on the other.

The probability of getting a 1 on one die is 1/6, because there are 6 numbers on a die and one of them is a 1.

The probability of getting a 1 on the other die is the same, 1/6, because the dice are the same.

So, 1/6 * 1/6 = 1/36.

Answer 5

Probability of getting a 1 on each die is 1/6 x 1/6 = 1/36

Answer 6

P(two 2`s) = (1 / 6) x (1 / 6) = 1 / 36

Answer 7

1/36

there are 36 ways to roll the dice and only one way to get a two.

Answer 8

(1,2) (2,1)
(2,2) (2,2)
(3,2) (2,3)
(4,2) (2,4)
(5,2) (2,5)
(6,2) (2,6)

p(a)=6 prob of getting 2 in first dice
p(b)=6 prob of getting 2 in second dice
p(a n b)=1 prob of intersection of a and b
we know that p(aUb)= p(a)+p(b)-p(a n b)
===> p(aUb) = 6+6-1
= 11
therefore ans is 11/36


If the sum of the number of two dice should be 2 then the ans is 1/6 *1/6 =1/36

Answer 9

1/6 (6 equal chances of landing on a certain number) for one di. Then you have to multiply that by two for two dice. 1/6X1/6=1/32.

Answer 10

that means you can have one 2, or two 2.
P = 1/6 + 1/6 + 1/6 * 1/6 = 13/36 = %36.1