There are 36 outcomes for rolling two dice (6 sides for each of 2 dice, 6^2 = 36). 4 of those combinations (3 and 6, 4 and 5, 5 and 4, and 6 and 3) have a sum of 9. So the probability of rolling a 9 is 4/36 = 1/9 or 0.111 or 11.1%.
2007-08-20 05:46:54
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answer #1
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answered by DavidK93 7
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3+6
4+5
6+3
5+4
there are 4 possible combinations
therefore the probability is 4/36 = 1/9
2007-08-20 12:47:15
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answer #2
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answered by civil_av8r 7
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sum 2 in 1 way
sum 3 in 2 ways..
sum 4 in 3 ways..
sum 5 in 4 ways..
sum 6 in 5 ways..
sum 7 in 6 ways..
sum 8 in 5 ways..
sum 9 in 4 ways..
sum 10 in 3 ways..
sum 11 in 2 ways..
sum 12 in 1 ways..
so the answer is 4/36
2007-08-20 12:49:16
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answer #3
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answered by nambi23 1
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A one in nine probability of success.
that's: 1/9
So simple when you know how.
Happy dice rolling.
2007-08-20 12:55:30
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answer #4
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answered by Dan 4
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There are a total of 36 outcomes. Out of these 36, only some combinations equal 9.
(3,6),(4,5),(5,4),and (6,3), which means that the probability is 11.1...% (4/36 = 0.1...)
EDIT: LAWL AT MASTERMIND
2007-08-20 12:47:56
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answer #5
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answered by Anonymous
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How many sided dice?
2007-08-20 12:46:23
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answer #6
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answered by Anonymous
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the probability is 4/36 ... because you have 36 different condition such as {(1,1) (1,2) (1,3) ...............(6,5) (6,6)}
but only sum of 4 of these pairs can be 9:
{(6,3) (5,4) (4,5) (3,6)}
so the answer is 4/36
2007-08-20 12:55:57
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answer #7
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answered by S N 1
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