math problem?

Question

how do you solve

P(p-3q)^2

?

Answer 1

P(p-3q)^2 (I am assuming you meant lower case p)
p(p^2 - 2(p)(3q) + (3q)^2) solve the ^2 part first
p(p^2 -6pq + 9q^2) simplify
p^3 - 6p^2q + 9pq^2 distribute the first "p"

I am assuming what you want is for this equation to be fully expanded as you didn't say to sovle p or q.

Answer 2

well im not sure about this are you just supposed to simplify the expression? you use order of operations so the exponent will go first. (p-3q) squared so (p-3q)(p-3q) which is p^2-3pq-3pq+9q^2. so that is (p^2-6pq+9q^2) then multiply that by the P. i dont know if P is the same as p so i will assume i dont really know if this is right in the first place but anyway..................P times the expression we got above should be if P=p it should be

(p^3-6qp^2+9pq^2)

i have no idea if that is right i did it logically way i was tought. if you have to sub the variables make sure you use the order of operations. what level math is this? sorry if that is wrong i think its right...capital P is same as small p right? just cuz it was in the beginning?

Answer 3

if it's P(p-3q)^2 then,

P(p^2-6pq+9q^2)

Pp^2-6Ppq+9Pq^2

but... if it is p(p-3q)^2 then,

p(p^2-6pq+9q^2)

p^3-6p^2q+9pq^2