please solve this 4 /x + 2/ - 3 < 13 this is absolute value inequalities?

Question

and also where can i find website with similar problems with that and please show solution thank you

Answer 1

4 |x + 2| - 3 < 13
4 |x + 2| < 16
|x + 2| < 4

If the absolute value of x+2 is less than 4, this means that the value of x+2 must be between 4 and -4. (If x+2 were less than -4, its absolute value would be greater than 4.)

-4 < x + 2 < 4

Subtract 2 from each expression in the inequality:

-6 < x < 2

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Checking the solution:

-7 is outside the range:
4 | -7 + 2 | - 3 =
4 * 5 - 3 =
17, which is NOT less than 13.

-5 is inside the range:
4 | -5 + 2 | - 3 =
4 * 3 - 3 =
9, which IS less than 13

Answer 2

4 |x + 2| - 3 < 13
4 |x + 2| < 16 add 3
|x + 2| < 4 divide by 4
-4 < x + 2 < 4 trap inside of | | between negative & positive
-6 < x < 2 subtract 2

Answer 3

4 |x + 2| - 3 < 13
4 |x + 2| < 16
|x + 2| < 4
-4 < x+2 < 4
-6 < x < 2


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Answer 4

i think of it incredibly is the thank you to set the subject up and the thank you to sparkling up it | 5 - 4x | > | - 13 | 5 + 4x > 13 -5 -5 4x > 8 4x 4x x > 2 i'm hoping it is right n keep in mind absolute values can't be unfavorable