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Write an equation in slope-intercept form that satisfies each given condition:

9. slope = -5, passes through (-3, -8)

How would I go about solving this problem?

2007-08-19 12:45:24 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

general equation is y = mx + b
slope = -5 makes it
y = -5x + b

plug in (-3,-8):

-8 = -5(-3) + b
-8 = 15 + b
-23 = b

finish: y = -5x - 23

2007-08-19 12:51:54 · answer #1 · answered by Philo 7 · 0 0

draw on a grid the point (-3,-8). Go down from that point five and go to the right one. Do this three times (until you get to the Y intercept). the equation would be Y= -5X - 23

2007-08-19 19:54:15 · answer #2 · answered by Anonymous · 0 0

Here is how I learned to solve these kinds of problems.

First, put it in point-slope form.

y-(y1)=m(x-(x1))
y-(-8)=(-5)(x-(-3))

Then solve for y.

y+8=-5(x+3)
y+8=-5x-15
y=-5x-23

2007-08-19 19:58:24 · answer #3 · answered by Misty 2 · 0 0

The form would be as follows:

y-(y1)=m * (x-(x1))

so y - (-8) = -5 * (x - ( -3))
y+8=-5x-15
y=-5x-23

2007-08-19 19:55:08 · answer #4 · answered by golffan137 3 · 0 0

Philo is correct

2007-08-19 19:53:08 · answer #5 · answered by bradlelf 2 · 0 0

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