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A mother’s age is the product of the sum and difference of the ages of her two children. If x and y are the ages of the children, express the mother’s age as a polynomial.

Please show how you get the answer please so I will understand.

2007-08-19 10:54:43 · 7 answers · asked by Sha722 1 in Education & Reference Homework Help

7 answers

The previous answers are correct, but you need to continue the multiplication to get the polynomial.

(x-y)*(x+y)

= x(sqaured) + xy - xy - y(squared)

= x(sq) - y(sq)

{sorry I don't know how to type the exponents here}

2007-08-19 11:09:30 · answer #1 · answered by Chewie 3 · 0 1

The product is the answer to a multiplication sum, so if the

children are x and y years old, then the sum of their ages is

[x+y] years, and the difference of their ages is [x-y] years, so

Mother`s age is;

[x+y][x-y]

=x[x-y]+y[x-y]

=x^2-xy+xy-y^2

=x^2-y^2 years.

Hope this helps, Twiggy.

2007-08-19 11:09:10 · answer #2 · answered by Twiggy 7 · 1 0

Ready? Let Mom be z. "Her age is" means
z=

Now, one child is x and the other is y.
the sum (means addition) of their ages is (x + y)
the difference (means subtraction) of their ages is (x-y)
What does product mean? Multiplication right?

so z=(x+y)(x-y)

Hope the explanation helps.

2007-08-19 11:01:51 · answer #3 · answered by USMCBabydoll 2 · 1 1

Okay, we can use the variable "z" for the mother's age. and "x" for child one and "y" for child two.

So, z=(x+y)(x-y)
Hope I helped!

2007-08-19 11:08:01 · answer #4 · answered by Ask this girl 5 · 0 0

ma = (x+y) * (x-y)
multiply the brackets x(x-y) + y(x-y) = x^2 -xy +yx -y^2
ma = x^2 -xy +yx - Y^2 # -xy +yx = 0
ma = x^2 - y^2

2007-08-19 11:22:43 · answer #5 · answered by mark 6 · 0 1

age=[x+y] [x-y]

2007-08-19 11:55:01 · answer #6 · answered by Vincent S 2 · 0 0

Mothers age=M

X-childs age.
Y-Childs age.

(X+Y)(X-Y)=M

I suppose.

2007-08-19 11:00:58 · answer #7 · answered by 552200154 3 · 0 1

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