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example: If I had a compound with 10.4% carbon, 27.8% sulfur, and 61.7% calcium. How can I find out its formula??

2007-08-19 10:34:29 · 3 answers · asked by iseeduckies 1 in Science & Mathematics Chemistry

3 answers

Here is what I get:

C.ratio = 10.4/12.011 = 0.866
S.ratio = m27.8/32.06 = 0.867
Ca.ratio = 61.7/40.08 = 1.539

Divide all ratios by 0.866.

C.rationorm=0.866/0.866 = 1.000
S.rationorm = 0.866/0.867 = 0.999
Ca.rationorm = 1.539/0.866 = 1.776


Now we need to turn all of these into integers. Multiply all by 9. I found 9 by trying numbers until all ratios were nearly integers.

C.rationorm=9
S.rationorm = 9 = 8.99
Ca.rationorm = 15.98

A reasonable empirical formula would be C9S9Ca16.

2007-08-19 13:06:10 · answer #1 · answered by Anonymous · 0 0

Simple - just replace the % signs by grams. Then divide by the Ar values as normal.

2007-08-19 18:33:52 · answer #2 · answered by Gervald F 7 · 0 0

You divide each % by the molecular weight of each element:
for example in your compound you will have
10.4/12.011 atoms of C
27.8/32.066 atoms of S
61.7/40.078 atoms of Ca

2007-08-19 19:33:55 · answer #3 · answered by Steve 2 · 0 0

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