Help With Balancing and Completing Equations?

Question

1. Complete and balance the nuclear equations for the following:

a) 2H + 2H --> 3H + ____.
b) 239Np --> β- + ___.
c) 226Ra --> α + ____.
d) 235U + 1n --> 160Sm + 3 1n + ____.
e) 22Na --> β+ + _____.

2. Balance the following equations:
a) I-(aq) + MnO4-(aq) --> I2(aq) + MnO2(aq) (basic solution)
b) IO3-(aq) + I-(aq) --> I-3(aq) (acidic solution)

1. Complete and balance the nuclear equations for the following:

a)2H + 2H --> 3H + ____.
b)239Np --> β- + ___.
c)226Ra --> α + ____.
d)235U + 1n --> 160Sm + 3 1n + ____.
e)22Na --> β+ + _____.

2. Balance the following equations:
a) I-(aq) + MnO4-(aq) --> I2(aq) + MnO2(aq) (basic solution)
b) IO3-(aq) + I-(aq) --> I-3(aq) (acidic solution)

I am unsure how to do these. If someone could set me in the right direction. xD

Answer 1

1)
a) 2H + 2H --> 3H + 1H
b) 239Np --> β- + 239Pu
c) 226Ra --> α + 222Rn
d) 235U + 1n --> 160Sm + 3*1n + 73Zn
e) 22Na --> β+ + 22Ne

2)
a)
I-(aq) + MnO4-(aq) --> I2(aq) + MnO2(aq)
Oxidation:
(2I- = I2 + 2e- ) x 3

Reduction:
( MnO4- + 2H2O + 3e- = MnO2 + 4OH- ) x 2

Global:
6I- + 2MnO4- + 4H2O = 3I2 + 2MnO2 + 8OH-

b)
IO3-(aq) + I-(aq) --> I-3(aq)
Can not balance:
Both semireactions are reductions:
Reduction:
IO3- --> I-3
I- --> I-3
Please check the I-3 ion (it is very rare)

Bye and good luck

Answer 2

Do you think we are peons doing all this crap for 2 points? Fuhgetaboutit.

Answer 3

Ba(+2) + CO3(-2) --> BaCO3