Wow, alot of incomplete answers so far..
If 2nd and 3rd are odd, then the last two must be even. Why? Because if one of them were odd, we'd have used up all the odds, and then the other one of them would be even. odd+even = odd, but you said they must equal 6. So that can't happen.
That means you have:
O O O E E
Thus the first number is what? Odd. You can't determine if it is 1, 3, or 5 - it could be any one of them.
In fact, you can rearrange the odds and evens among themselves any way you like and you'd still meet these conditions. There are:
3!2! = 3×2×1×2×1 = 12 such rearrangements, listed below:
13524
15324
31524
35124
51324
53124
13542
15342
31542
35142
51342
53142
2007-08-19 09:10:40
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answer #1
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answered by сhееsеr1 7
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there are many arrangements
5 1 3 2 4, 5 1 3 4 2, 5 3 1 2 4, 5 3 1 4 2
3 1 5 2 4, 3 1 5 4 2 , 3 5 1 2 4, 3 5 1 4 2
1 3 5 2 4, 1 3 5 4 2, 1 5 3 2 4, 1 5 3 4 2
So the first number is 1 or 3 or 5
2007-08-19 16:23:34
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answer #2
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answered by mohanrao d 7
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5, 1, 3, 2, 4
5, 1, 3, 4, 2
5, 3, 1, 2, 4
5, 3, 1, 4, 2
3, 1, 5, 2, 4
3, 1, 5, 4, 2
3, 5, 1, 2, 4
3, 5, 1, 4, 2
1, 3, 5, 2, 4
1, 3, 5, 4, 2
1, 5, 3, 2, 4
1, 5, 3, 4, 2
so the first number could either be 5, 3, or 1
2007-08-19 16:25:40
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answer #3
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answered by tammy 3
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couldnt it be:
1, 3, 5, 4, 2
4+2 = 6
and
3 and 5 are odd.
but then you could also rearrange the first three numbers because they are all odd. it doesnt seem too clear :/
2007-08-19 16:10:38
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answer #4
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answered by cow 1
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Hmmmmm...........
1 3 5 6 4 2
?????
2007-08-19 16:08:39
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answer #5
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answered by kj 7
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13542 or 13524 or 15324 or 15342
2007-08-19 16:07:16
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answer #6
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answered by ironduke8159 7
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not unique:
13542
31542
51342
2007-08-19 16:08:00
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answer #7
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answered by John V 6
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