how can i factor this: (x^2-9)(x^2+1)^(1/2)-(x^2-9)(x^2+1)^(3/2)?

Question

please explain

Answer 1

presuming u meant: "(x^2 - 9)*[(x^2 +1)]^1/2 - (x^2 -9)(x..."

Type out the question in full, only can do the following from what you gave using my 1st interpretation of question:

[(x-3)(x+3)]*[ ( (x^2 + 1)^1/2) - (x ...) ]

- Taking out (x^2 - 9) as common factor and using difference of 2 squares.

Answer 2

(x^2-9)(x^2+1)^(1/2)-(x^2-9)(x^2+1)^3/2
=(x^2-9)[(x^2+1)^1/2 - (x^2+1)^3/2]
= [(x^-9)(x^2+1)^1/2][1 -(x^2+1)]
= [(x+3)(x-3)(x^2+1)^1/2](-x^2)