solve for u and v in terms of x and y and check.
x=2+3u+7v
y=-3+2u+5v
u=(x-3u-7v) /2
y=-3+2(x-3u-v) /2
am i starting out right?
2007-08-19 06:44:32 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x=2+3u+7v <-- Eq1
y=-3+2u+5v <-- Eq 2
-2x = -4 -6u -14v <-- Eq 3 = -2*Eq 1
3y = -9 +6u +15v <-- Eq4 = 3* Eq2
-2x+3y = -13 +v <-- Eq 3 + Eq 4
v =13 - 2x +3y
Now get u by substituting 13-2x+3y for v in Eq 1.
x = 2+3u +91 -14x +21y
15x -21y -93 = 3u
u = 5x -7y -31
I'll leave the checking to you.
2007-08-19 07:03:15 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
x=2+3u+7v......(1)
y=-3+2u+5v......(2)
2*(1) - 3*(2):2x-3y = 13-v
=> v = 13-2x+3y
From (2),
u = (3+y-5v)/2
Can you finish it now?
2007-08-19 06:54:10 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
correct answer
v=3y-2x-5
u=5x-7y+11
2007-08-19 07:15:07 · answer #3 · answered by prem l 1 · 0⤊ 0⤋