Find the area of a trapezoid with bases 21in and 37in and a height of 15in.
2007-08-19 05:49:01 · 8 answers · asked by Adrienne W 1 in Science & Mathematics ➔ Mathematics
A = (1/2) (15) (21 + 37) in ²
A = (1/2) (15) (58) in ²
A = 435 in ²
2007-08-22 07:07:44 · answer #1 · answered by Como 7 · 1⤊ 0⤋
area of a trapezoid =average base xheight
= 21 +37/2 x 15 = 435 in²
2007-08-19 06:51:28 · answer #2 · answered by mramahmedmram 3 · 0⤊ 0⤋
The area of a trapezoid is A=(base1+base2)*height/2
base1=21 in
base2=37 in
height=15 in
A=(21+37)*15/2
A = 475 in²
Greetings
2007-08-19 06:01:05 · answer #3 · answered by Gilarh 3 · 0⤊ 0⤋
area of the trapezoid =(20+28)/2*36 =864cm^2 area into the height of the base = volume of the pyramid 3168cm^3/864cm^2 =3.7cm
2016-05-17 08:05:35 · answer #4 · answered by ? 3 · 0⤊ 0⤋
Area of the trapezium=(B+b)*h/2
=(21+37)*15/2
=29*15
=435 in^2.ANS.
2007-08-19 06:03:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋
The area of a trapezoid is:
(base1+base2) times height times 1/2
2007-08-19 06:03:17 · answer #6 · answered by ben80 2 · 0⤊ 0⤋
Use the trapezoid area formula:
1/2h(b#1+b#2)
1/2*15 (21+37)
1/2*15*58
29*15
435 sq. in.
2007-08-19 06:05:01 · answer #7 · answered by Anonymous · 0⤊ 0⤋
(21+37)*15/2=435
2007-08-19 05:58:21 · answer #8 · answered by Newlenston 2 · 0⤊ 0⤋