One number is 3 less than another. If 10 times the smaller number minus 3 times the larger number is 33, find the two numbers
2007-08-19 04:43:47 · 7 answers · asked by tbond_1969 1 in Science & Mathematics ➔ Mathematics
x represents the smaller number and y represents the larger number.
x+3=y
10x-3y=33
subsitute y for x+3 ..therefore
10x-3(x+3)=33
10x-3x-9=33
7x-9=33
7x=33+9
7x=42
7x/7=42/7
x=6
now to figure out y..
x+3=y
6+3=9
y=9
hope that helps :)
2007-08-19 04:59:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let the larger number be "N"
Then the smaller one will be "N-3"
By the statement'
10 x (N-3) - 3 x N = 33
10N - 30 -3N = 33
10N - 3N = 33 + 30
7N = 63
N = 63 / 7 = 9...(The larger number)
The smaller number = 9 - 3 = 6
Hence the numbers are "9" and "6"
. . . . . . . . . ==================
2007-08-23 11:46:31 · answer #2 · answered by Joymash 6 · 0⤊ 0⤋
the numbers are 6 and 9.
2007-08-19 11:54:46 · answer #3 · answered by Nathan W 1 · 0⤊ 0⤋
6 and 9 are the two numbers.
2007-08-19 11:50:27 · answer #4 · answered by Erulechto 3 · 0⤊ 0⤋
Let x ----------the larger number
x - 3 ----------the smaller number
10 (x-3) -----10 times the smaller number
3x -------------- 3 times the larger number
10(x-3) - 3x = 33
10x -30 - 3x = 33
10x - 3x = 33 + 30
7x = 63
x = 63/7 = 9 larger number
9 - 3 = 6 smaller number
2007-08-23 08:18:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x=y-3
10x-3y=33
=>10(y-3)-3y=33
=>7y = 63
=> y=9
=> x=6
The numbers are 6 and 9.
2007-08-19 11:51:58 · answer #6 · answered by ?????? 7 · 1⤊ 0⤋
x = y + 3
10y - 3x = 33
10y - 3y - 9 = 33
7y = 42
y = 6
x = 9
2007-08-19 11:54:43 · answer #7 · answered by Helmut 7 · 0⤊ 0⤋