a sample of radium-226 has a mass of 100mg. find a formula for the mass of radium-226 that remains after t years
2007-08-19 01:47:36 · 5 answers · asked by deadman 2 in Science & Mathematics ➔ Mathematics
Hi,
A = 100(½)^(t/1590) is the formula that would give the mass of radium-226 left after t years.
I hope that helps!! :-)
2007-08-19 01:56:07 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
Radium-226 decreases half of its mass every 1590 years..
therefore, after t years...
the mass of Radium 226 will become
100 (1/2)^(t / 1590)
2007-08-22 20:51:03 · answer #2 · answered by >bLueeyes< 2 · 0⤊ 0⤋
Radium-226 reduces half of its mass every 1590 years. So the rate is 1/2
m(t) = 100 (1/2)^(t / 1590)
2007-08-19 01:56:13 · answer #3 · answered by 7 · 0⤊ 0⤋
I did not have the possibility to read the number . i suppose it is 3
so, as 3 is small versus 1590 use the derivative and write
dm = - lambda m dt
lambda = ln2/half time =4.359*10^-4
dm = - 4.359*10^-4*3 *100=-0.13g
you have so 100-0.13 =99.87g
2007-08-19 01:56:38 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
t.m/(1590*2);
where t= time period in years;
m= mass of the sample;
2007-08-19 01:58:17 · answer #5 · answered by karan s 3 · 0⤊ 0⤋