please tell how to find f(x+2)
2007-08-18 20:45:48 · 6 answers · asked by hindol g 1 in Science & Mathematics ➔ Mathematics
f(x+2) = f(x-2+4) = 4(x+4) - 5 = 4x+11
2007-08-18 20:51:17 · answer #1 · answered by Derek C 3 · 0⤊ 0⤋
i would say:
f(x-2) = 4x -5 = 4(x-2) +3
hence f(x+2) = 4(x+2) + 3 = 4x +11
2007-08-18 20:51:22 · answer #2 · answered by trop de choses 1 · 1⤊ 0⤋
f(x+2) = 4(x+2)-5
f(x+2) = 4x+8-5 = 4x+3
2007-08-18 22:55:40 · answer #3 · answered by Sarah 1 · 0⤊ 0⤋
Let u = x - 2 then x = u + 2
f(x - 2) = f(u) = 4(u + 2) - 5 = 4u + 3
Set u = x+ 2 then:
f(x+2) = 4(x + 2) + 3 = 4x + 11
2007-08-18 20:53:52 · answer #4 · answered by Captain Mephisto 7 · 0⤊ 0⤋
O.O fun.
since f(x-2) = 4x-5,
Therefore the equation will be like,
f(x) = 4x + k, whereby k is a certain number.
f(x-2) = 4x -8 - k
= 4x - 5
Therefore,
4x - 5 = 4x - 8 - k.
k = -3
Therefore f(x) = 4x - 3
f(x-2) = 4(x-2) -3
= 4x -11
Solved.
:D
Hope this helps!
2007-08-18 23:54:01 · answer #5 · answered by noel 2 · 0⤊ 0⤋
f(x-2)=4x - 5
Substitute x - 2 into x in the equation
f(x - 2) = 4 (x - 2) - 5
f(x - 2) = 4x - 8 - 5
f(x - 2) = 4x - 13
2007-08-19 01:55:06 · answer #6 · answered by 痴心情长剑 3 · 0⤊ 0⤋