How do you solve this math problem?

Question

Hey I was wondering if anyone could tell me how to solve this KIND of math problem. I wanna know how.

Jim can fill a pool carrying bucks of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together?

Thank you.

Answer 1

jim can do it in 30 min
sue can do it in 45 min so he is equal to 30/45 of jim
tony can do it in 90 min so he is equal to 30/90 of jim
So 1+30/45+30/90 of jim have to do the work which is equal to 90/90+60/90+30/90=180/90=2jim
so all three can do the work in half time of jim that is 15 min
this can be solved by deriving the HCF of all three that is once more 15 minute

Answer 2

if you missed it the first time

It doesn't say how many buckets of water the pool holds, but you can make something up and work it out from there. The answer will be the same no matter what you make up for the pool capacity.

Let's say it holds 30 buckets.

That means Jim carries 1 bucket /minute
Sue carries 2/3 bucket/minute
Tony carries 1/3 bucket/minute.

For each minute that passes, the 3 of them carry
(1+2/3+1/3=) 2 buckets of water.
The whole pool holds 30 buckets so they are done in
(30/2=) 15 minutes.

Does this make sense? Yes, because the three of them working together should get it done faster than the fastest one working alone.

So the steps are:
1. Make up a capacity for the pool that will make the math easy.
2. Figure out a per-minute rate at which each person works.
3. Add up all the per-minute rates to get a total per-minute rate when they all work simultaneously.
4. Divide the total capacity by the total per-minute rate.

2 minutes ago - Report Abuse

Answer 3

It doesn't say how many buckets of water the pool holds, but you can make something up and work it out from there. The answer will be the same no matter what you make up for the pool capacity.

Let's say it holds 30 buckets.

That means Jim carries 1 bucket /minute
Sue carries 2/3 bucket/minute
Tony carries 1/3 bucket/minute.

For each minute that passes, the 3 of them carry
(1+2/3+1/3=) 2 buckets of water.
The whole pool holds 30 buckets so they are done in
(30/2=) 15 minutes.

Does this make sense? Yes, because the three of them working together should get it done faster than the fastest one working alone.

So the steps are:
1. Make up a capacity for the pool that will make the math easy.
2. Figure out a per-minute rate at which each person works.
3. Add up all the per-minute rates to get a total per-minute rate when they all work simultaneously.
4. Divide the total capacity by the total per-minute rate.

Answer 4

the answer is 15 minutes because in 15 minutes Jim has it half full, sue has it 1/3 full and tony has it 1/6 full.

it's 15 minutes because 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 1 full pool

Answer 5

since the majority of the time is in minutes then convert everything to minutes. now convert 1.5 hrs to 90 mins since 1 hr = 60 mins and the rest half hr = 30 mins. now take the lowest common multiple of 30, 45 and 90, which is 90. So its gona take 90 mins for all three to quickly fill the pool together.

Answer 6

Screw it just have jim do it!!!!!!!! he does it in 30 mins!!!!!!