I think you meant to put parentheses around (x+h) and not the whole fraction.
(1/(x+h) +1/x) / x
First start with the top by getting a common denominator.
1/(x+h) + 1/x
= x/[x(x+h)] + (x+h)/[x(x+h)]
= (x +x+h) / [x(x+h)]
= (2x+h) / [x(x+h)]
The last step is to divide by x.
((2x+h) / [x(x+h)]) / x
= ((2x+h) / [x(x+h)]) (1/x)
= (2x+h) / [x^2 (x+h)]
2007-08-26 11:31:36
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answer #1
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answered by MsMath 7
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1/x=h
2007-08-25 16:34:38
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answer #2
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answered by Anonymous
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Remove the parentheses around 1/x+h, they are useless.
(1/x+h+1/x)/x
1/x + 1/x = 2/x, so...
(2/x+h)/x
Dividing by x is the same as multiplying by 1/x. So multiply each term in the numerator by 1/x, to get rid of that ugly double fraction. Your final answer is...
2/x^2 + h/x
2007-08-19 01:18:22
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answer #3
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answered by Master Maverick 6
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Add (1/x+h)= Result#1
Now add (Result#1) +(1/x)= Result#2
Finally, (Result#2/x)
Hint: common denominators!
2007-08-19 03:37:32
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answer #4
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answered by Journeyman 2
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get rid of the brachets first and keep doing it until there are no brachets that makes it easier
2007-08-19 01:28:32
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answer #5
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answered by Anonymous
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( 2x+h ) / x = 2 + (h / x)
2007-08-19 01:28:13
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answer #6
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answered by Will 4
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