2007-08-18 17:48:52 · 9 answers · asked by C00L GαL 2 in Science & Mathematics ➔ Mathematics
Graphically:
Plug in
as Y1: 2x-sinx-xcosx
as Y2: 0
Graph and find their intersecting point.
It is zero. So x=0
2007-08-26 14:59:11 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x=0
2007-08-26 01:33:28 · answer #2 · answered by vr n 2 · 0⤊ 0⤋
x=0
2007-08-25 09:43:23 · answer #3 · answered by GB 2 · 0⤊ 0⤋
Not sure how to solve it algebraically, but I drew the graph quickly to see that x is 0.
2007-08-19 00:58:32 · answer #4 · answered by douglas 2 · 0⤊ 0⤋
2x-x(sinx/x+cosx)=0
2x-x(1+cosx)=0 .....sinx/x=1
2x-x-xcoss=0
x-xcosx=0
x=xcosx
cosx=x/x
cosx=1
x=inv of cos
x= sec
2007-08-19 01:22:18 · answer #5 · answered by MOHAMED 1 · 0⤊ 1⤋
x = 0 by observation because 2(0)-sin0-0cos0 = 0
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This problem can be either solved numerically or by observation.
2007-08-19 00:53:45 · answer #6 · answered by sahsjing 7 · 0⤊ 1⤋
x=0 lol it is bluddy easy
try it with x
like (2 * x)-(sin0 =0)-(cos0=0)
0-0-0=0 lol
2007-08-19 00:53:05 · answer #7 · answered by oOo_tophothari_oOo 3 · 1⤊ 2⤋
it cant be 0! ( for the other answers) cause its a "-" sign instead a "X" sign.. it would be 0 if there are multiplications...
2007-08-19 01:09:21 · answer #8 · answered by Anonymous · 0⤊ 3⤋
THANKS SRITI YOURS SIR MUNISH DADHWAL
2007-08-22 13:22:56 · answer #9 · answered by munish T 1 · 0⤊ 0⤋