(-243)^1/5
i just forgot what youre supposed to do if its a negative number...
2007-08-18 15:42:05 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(-1)^(1/5) 3
= - 3
Check
(-3)^5 = (-3) x (-3) x (-3) x (-3) x (-3)
= 9 x 9 x (- 3)
= - 243
2007-08-21 23:17:11 · answer #1 · answered by Como 7 · 2⤊ 0⤋
1/243^1/5 you reciprocate the negative number in order to get the positive number so one over 5th root of 243 but I think -243 is divisble to an exponent of 5 so you will not need to reciprocate you will got an answer of -3 thats the answer to the question. so if you want a positive answer its just 1/3. hope I helped you
2007-08-18 22:59:24 · answer #2 · answered by dodong1127 2 · 0⤊ 0⤋
Fractional exponents are equivalent to taking that root of the number. In that example, it's taking the fifth root of -243. Since this is an odd root, it's possible to evaluate it and come up with a real answer. The answer is -3.
If it's an even root (Ex. (-25)^(1/2) ), you have to factor out i, which is the square root of negative one (In that example, the answer is 5i).
2007-08-18 22:51:37 · answer #3 · answered by Necraz 1 · 0⤊ 0⤋
(-243)^1/5
factor 243
243 = 9(27)= 9^2(3) = 3^5
(-243)^1/5 = (-3^5)^(1/5) = (-1)^(1/5) x 3
there are 5 (complex & real) 5th roots of (-1)
2007-08-18 22:50:07 · answer #4 · answered by vlee1225 6 · 0⤊ 0⤋