Find k when x = 6, z = - 2, y = - 15
2007-08-18 15:06:58 · 7 answers · asked by Dudemanbro 1 in Science & Mathematics ➔ Mathematics
y = k x / z
z y / x = k
(- 2)(-15) / 6 = k
k = 5
2007-08-22 05:16:48 · answer #1 · answered by Como 7 · 1⤊ 0⤋
y= K x/z then - 15 = K 6/- 2 then K=5
2007-08-19 00:30:46 · answer #2 · answered by mramahmedmram 3 · 0⤊ 0⤋
If x varies right away with y, there's a ok so as that x=yk. If x=40 8 whilst y=8, then ok=40 8/8=6 So whilst y=12, x=12*6=seventy two If x varies înversely with z^2, there's a p so as that x * z^2=p. If x=40 8 whilst z=3, p=40 8*3^2=40 8*9=432. whilst z=2, z^2=4 and x=p/4=108
2016-10-16 02:19:00 · answer #3 · answered by ? 3 · 0⤊ 0⤋
y=kx/z is the expression you start with. Then plug in the know values to get:
-15=k (6/-2)=-3k
thus k=5
2007-08-18 15:12:39 · answer #4 · answered by VampireDog 6 · 1⤊ 0⤋
Hmm...
I hope I got this right...
y = kx / z
-15 = k(6) / (-2)
30 = k(6)
k = 5
2007-08-18 15:14:34 · answer #5 · answered by Enigmatically Poetic 2 · 0⤊ 0⤋
y = kx / z
- 15 = 6k / - 2
- 15 = - 3k
- 15 / - 3 = k
5 = k
Answer: k is 5
Proof:
- 15 = 6(5) / - 2
- 15 = 30 / -2
- 15 = - 15
2007-08-22 14:11:03 · answer #6 · answered by Jun Agruda 7 · 3⤊ 1⤋
y = x/z
y = x direct variation
y = 1/z inverse variation
if an equation is not given then: y = k(x/z)
2007-08-18 15:11:51 · answer #7 · answered by sloppyjoe2 2 · 0⤊ 0⤋