solve system of equations?

Question

9x -2y = 28
y= -3x + 1

Answer 1

9x - 2(-3x + 1) = 28
9x + 6x - 2 = 28
15x = 30
x = 2
y = - 6 + 1
y = - 5
Solution is x = 2 , y = - 5

Answer 2

9x -2y = 28
y= -3x + 1

try eliminate y from the equation
from 2nd eqn:
2y = -6x +2
substitue into 1st eqn
9x - ( -6x + 2) = 28
9x + 6x - 2 = 28
15x - 2 = 28
15x -2 +2 = 28 + 2
15x = 30
x = 2
y = -3x +1 = -3(2) + 1 = -6 + 1 = -5

Answer 3

look at me...trust me im right!!

step 1: substitute "-3x+1" for 'y" in the original equation!
for example:
9x-2(-3x+1)=28

step2: now u have to get rid of the parenthesis! multiply "-2" by (-3x+1)!

step3: now u have, 9x+6x-2=28! now u must combine like terms, add "9x" and "6x"! now u have
15x-2=28!

step4: add a "+2" to the "-2" and "28". what u do to one side of the equal sign u must do to the other side!
15x-2=28
15x+2=+2

step5: the "+2" and "-2" cancelled out, leaving u with:
15x=30

step6= now u need to find the value of "x", so divide 15 by each side!
15x=30
-------------
15

x=2!!!!!!!!!!!!

step7: now substitute "x=2" into "y=-3x+1" from the original equation, to find the value of "y"!
y=-3x+1
y=-3(2)+1
y=-6+1
y=-5!!!!!!!!!!!!!

now substitute the values for y and x in the original equation:
9x-2y=28
9(2)-2(-5)=28
18+10=28
28=28!!!!
yes the values are true!! trust me im right, this is the way u will understand:)

Answer 4

9x - 2y = 28 >>>>>>>>>>>>>>equation 1
y = - 3x + 1 >>>>>>>>>>>>>>equation 2

From equation 2, y = -3x + 1
Plug it into equation 1
9x - 2y = 28
9x - 2(-3x + 1) = 28
9x + 6x - 2 = 28
15x = 28 + 2
15x = 30
x = 30 / 15
x = 2

Plug x = 2 into equation 2
y = - 3x + 1
y = -3(2) + 1
y = -6 + 1
y = -5

Thus x = 2 , y = -5

Answer 5

1) 9x-2y=28
3x+y=1
make one coefficient the same
2) 9x-2y=28
9x-3y=3
then sutract it
3) y=25

Answer 6

X= -2
Y=5
is d ans.