okay. i have a math test monday and i am reviewing and i came across a question and i am stuck! please help me! i would really appreciate it!
If a garden box is x by x feet and an area in ft^2 is twice the perimeter, what is the value for x that satisfies the requirements?
please explain how to do this math problem! thank you soooooooo much!
2007-08-18 14:08:14 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
perimeter is 4x (all four sides)
area is x squared
the area is twice the perimeter 2x squared
so 2(4x)=x squared
8x=x squared
8=x squared/x 8=x
perimeter 4*8=32
area 8squared=64 which is twice the perimeter
2007-08-18 14:21:36 · answer #1 · answered by siamcatp 4 · 0⤊ 0⤋
Area = x times x = x^2
Perimeter = x+x+x+x = 4x
The area (x^2) is (=) twice the perimeter 2(4x) --->
x^2= 2 (4x)
x^2=8x
x=8 feet
2007-08-18 21:16:02 · answer #2 · answered by G.V. 6 · 0⤊ 0⤋
Area = x², and, since all 4 sides are equal,
perimeter is 4x.
So, x² = 2(4x) = 8x
x(x-8) = 0.
Since x is not 0,
x = 8.
Check: area = 64, perimeter= 32.
2007-08-18 21:15:16 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
Since all the sides are equal, it is a square.
area = 2(perimeter)
x^2 = 2(4x)
x^2 - 8x = 0
x(x - 8) = 0
x = 8 ft
2007-08-18 21:15:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋