can some one help me with m^3 -9m^2 n + 18n^2 m?

Question

can some one help me with this problem

Answer 1

To factor it?

m (m - 6n) (m - 3n)

I first factored out m, since all terms have a factor of m in them. This left:

m^2 - 9mn + 18n^2

That's a quadratic. You need two negative numbers whose sum is -9 and whose product is 18. -6 and -3 fit those criteria.

Answer 2

First I'll factor a bit
m(m^2 -9mn+18n^2)
Now I can factor what's inside the brackets
m(m-6n)(m-3n)
That's it. Good luck!

Answer 3

factor out an m from all terms: m (m^2 - 9mn + 18n^2)
factor your trinomial: m (m - 6n)(m - 3n)