Solve for Z?

Question

y^2 + 3yz - 8z - 4x = 0


I have a few other problems like this and I dont know how to figure it out so any work would help a lot. Thanks.

Answer 1

Hi,


y² + 3yz - 8z - 4x = 0

Move all terms without z to the other side.

3yz - 8z = -y² + 4x

Factor "z" out on the left side as a common factor.

z(3y - 8) = -y² + 4x

Divide both sides by the expression 3y - 8 to get z alone.

-y² + 4x
----------- = z
3y - 8

That's your answer! I hope that helps!! :-)

Answer 2

"Solve for Z" is code for "get +1z all by itself on one side of the equation, preferably the left side".
You have one equation and 3 variables, so there"s no hope of getting hard answers-you need one equation for every variable. OK, enough talk.
y^2 +3yz -8z -4x=0
3yz-8z = 4x-y^2
z(3y-8)=4x-y^2
z= (4x-y^2)/(3y-8)

We're done.Good luck with your math work.

Answer 3

y² - 3yz - 8z - 4x = 0

Transpose y²

y² - 3yx - 8z - 4x - y² = 0 - y²

- 3yz - 8z - 4x = - y²

Transpose 4x

- 3yx - 8x - 4x + 4x = - y² + 4x

- 3yx - 8z = - y² + 4x

(- 3yz - 8z) = - y² + 4x

Factor out z

z( - 3y - 8) = - y² + 4x

Divide both sides of the equation by (- 3y - 8)

z(3y - 8) / (3y - 8) = - y² + 4x / (3y - 8)

x = - y² + 4 / (3y - 8)

- - - - - - - - s-

Answer 4

you cannot solve for z unless you have 2 more equations with the same variables

Answer 5

The solution is:

ZzZzZzZzZz...

Huh? Where am I?