Find the distance from P1 to P2.
(1) P1 = (0, 0, 0) and P2 = (1, -2, 3)
(2) P1 = (-2, 2, 3) and P2 = (4, 0, -3)
2007-08-18 03:29:42 · 4 answers · asked by journey 1 in Science & Mathematics ➔ Mathematics
(1) P1=(x1,y1,z1) and P2=(x2,y2,z2)
d=sqr ((x2-x1)²+(y2-y1)²+(z2-z1)²)
d=sqr ((1-0)²+(-2-0)²+(3-0)²)
d=sqr (1+4+9)
d=3.74
(2) P1=(x1,y1,z1) and P2=(x2,y2,z2)
d=sqr ((x2-x1)²+(y2-y1)²+(z2-z1)²)
d=sqr ((4+2)²+(0-2)²+(-3-3)²)
d=sqr (36+4+36)
d=8.72
greetings
2007-08-18 03:46:51 · answer #1 · answered by Gilarh 3 · 1⤊ 0⤋
Question 1
d ² = 1 ² + (- 2) ² + 3 ²
d ² = 1 + 4 + 9
d = √14
Question 2
d ² = 36 + 4 + 36
d ² = 76
d = 2√19
2007-08-18 03:47:39 · answer #2 · answered by Como 7 · 0⤊ 0⤋
d = √(x1--x2)² + (y1-y2)² =(z1-z2)²
1) = √1²+2²+3² = √14
2) = √6²+(-2)² + (-3-3)² = √76 = 2√19
2007-08-18 03:53:46 · answer #3 · answered by chasrmck 6 · 0⤊ 0⤋
(1) sqrt(5)
(2) sqrt(40)
2007-08-18 03:36:42 · answer #4 · answered by Shenya 2 · 0⤊ 0⤋