2x = 12 + 3y
3y = 2x - 12
y = (2/3) x - 4
2007-08-21 10:06:34
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answer #1
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answered by Como 7
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getting the y, you can produce the y-slope form or y=mx + b
m=slope b=intercept
given equation : 2x - 3y = 12
1. transfer 2x to the other side, i mean near 12,
(---transfering something to the otherside will make its sign changed ex. x+1=0 ; x=-1..or x-1=0 ; x=1)
* you will produce -3y =-2x + 12
2. divide it using the # near the y (its sign will follow)
*(-3y = -2x + 12)/3 or (-3/-3)y = (-2/-3)x + (12/-3)
answer: y=(2/3)x - 4
slope=2/3 intercept = -4
if you want to graph it, try this through substitution
x 0; 3; 6
y -4; -2; 0
how did I get this one?
let the value of x = 0
y=(2/3)(0) - 4
y=0 - 4
y= -4
let the value of y = 0
0=(2/3)x - 4
-(2/3)x = -4
-2x= -4 x 3
-2x = -12
(-2/-2)x = -12/-2
x=6
then graph it. because the slope is positive the line must me ascending( / ) from left to right
2007-08-18 01:10:54
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answer #2
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answered by lord_hdohjah 1
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y=4
2007-08-17 23:35:38
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answer #3
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answered by Anonymous
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You'd simply want to put that in y=mx+b form:
-3y = -2x+12
y=(2/3)x - 4
2007-08-17 23:32:43
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answer #4
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answered by magiscoder 3
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y = 2x/3 -4
2007-08-17 23:54:15
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answer #5
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answered by Anonymous
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2x - 3y = 12
3y = 2x - 12
y = (2/3)(x - 6)
2007-08-17 23:47:08
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answer #6
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answered by Anonymous
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3y= 2x-12
y= (2x-12)/3
2007-08-17 23:38:53
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answer #7
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answered by pigley 4
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y = (2x-12)/3
2007-08-17 23:32:04
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answer #8
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answered by ? 5
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