a line passing through (-6,-5) and (-1,y) is perpendicular to a line with slope -5/13. Find the value of y.?

Answer 1

(y-(-5))/(-1-(-6)) = - 13/5
(y+5)/5 = -13/5
y+5 = -13
y = -18

Answer 2

-13/5=(y+5)/(-1+6)
-13/5=(y+5)/5
-13=y+5
y=-13-5=-18

Remark
theb perpendicular slope =-5/13 so the slope=-13/5

Answer 3

the pair of points have the following slope:
(y2-y1)/(x2-x1) = (y - 5) / (-1 - (-6))
= (y-5)/ 5
the slope perpendicular to m is -1/m, so
slope perpendicular to -5 /13 is 13/5
so
(y - 5) / 5 = 13/5
y - 5 = 13
y =18

Answer 4

A(-6,-5)
B(-1,y)

AB=(5,y+5) --> slope_1=(y+5)/5
slope_2=5/13

and perpendiculars --> slope_1 ·slope_2 =-1
--> (y+5)/5 · 5/13 = -1 --> y = -5-13 = -18

Saludos.

Answer 5

first get the perpendicular slope;
m= -13/5
make an equation using point slope form;
(y+5)= (-13/5)(x+6)
y+5=(-13x-78)/5
5y+25= -13x-78
5y+13x+103=0
substitute x= -1, then solve for y;
5y+(13)(-1)+103=0
5y-13+103=0
5y+90=0
5y= -90
y= -90/5
y= -18